111313011113 has 2 divisors, whose sum is σ = 111313011114. Its totient is φ = 111313011112.

The previous prime is 111313011091. The next prime is 111313011143. The reversal of 111313011113 is 311110313111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63329232409 + 47983778704 = 251653^2 + 219052^2 .

It is a cyclic number.

It is not a de Polignac number, because 111313011113 - 2¹⁰ = 111313010089 is a prime.

It is a super-2 number, since 2×111313011113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111313011091 and 111313011100.

It is not a weakly prime, because it can be changed into another prime (111313011143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656505556 + 55656505557.

It is an arithmetic number, because the mean of its divisors is an integer number (55656505557).

Almost surely, 2^111313011113 is an apocalyptic number.

It is an amenable number.

111313011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111313011113 is an equidigital number, since it uses as much as digits as its factorization.

111313011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 17.

Adding to 111313011113 its reverse (311110313111), we get a palindrome (422423324224).

The spelling of 111313011113 in words is "one hundred eleven billion, three hundred thirteen million, eleven thousand, one hundred thirteen".