Base | Representation |
---|---|
bin | 110011110101011000… |
… | …1011100000111000111 |
3 | 101122022121001212001102 |
4 | 1213222301130013013 |
5 | 3310432112324033 |
6 | 123045252050315 |
7 | 11020303661165 |
oct | 1475261340707 |
9 | 348277055042 |
10 | 111313011143 |
11 | 43231324894 |
12 | 196a660399b |
13 | a65c53c189 |
14 | 555d730235 |
15 | 2d67507de8 |
hex | 19eac5c1c7 |
111313011143 has 2 divisors, whose sum is σ = 111313011144. Its totient is φ = 111313011142.
The previous prime is 111313011113. The next prime is 111313011163. The reversal of 111313011143 is 341110313111.
It is an a-pointer prime, because the next prime (111313011163) can be obtained adding 111313011143 to its sum of digits (20).
It is a strong prime.
It is an emirp because it is prime and its reverse (341110313111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111313011143 - 26 = 111313011079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111313011113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656505571 + 55656505572.
It is an arithmetic number, because the mean of its divisors is an integer number (55656505572).
Almost surely, 2111313011143 is an apocalyptic number.
111313011143 is a deficient number, since it is larger than the sum of its proper divisors (1).
111313011143 is an equidigital number, since it uses as much as digits as its factorization.
111313011143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 111313011143 its reverse (341110313111), we get a palindrome (452423324254).
The spelling of 111313011143 in words is "one hundred eleven billion, three hundred thirteen million, eleven thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •