Base | Representation |
---|---|
bin | 10000001100101011110… |
… | …010010010000011100111 |
3 | 10221102012000121100021001 |
4 | 100030223302102003213 |
5 | 121214143032143421 |
6 | 2211210531134131 |
7 | 143264266333426 |
oct | 20145362220347 |
9 | 3842160540231 |
10 | 1113131131111 |
11 | 39a09256016a |
12 | 15b895444347 |
13 | 80c773a053c |
14 | 3bc394092bd |
15 | 1de4d6a6691 |
hex | 1032bc920e7 |
1113131131111 has 2 divisors, whose sum is σ = 1113131131112. Its totient is φ = 1113131131110.
The previous prime is 1113131131097. The next prime is 1113131131121. The reversal of 1113131131111 is 1111311313111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1111311313111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113131131111 - 237 = 975692177639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113131131121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556565565555 + 556565565556.
It is an arithmetic number, because the mean of its divisors is an integer number (556565565556).
Almost surely, 21113131131111 is an apocalyptic number.
1113131131111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113131131111 is an equidigital number, since it uses as much as digits as its factorization.
1113131131111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27, while the sum is 19.
Adding to 1113131131111 its reverse (1111311313111), we get a palindrome (2224442444222).
The spelling of 1113131131111 in words is "one trillion, one hundred thirteen billion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred eleven".
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