Base | Representation |
---|---|
bin | 10100101110111101… |
… | …00101011111100111 |
3 | 1001201202112020120122 |
4 | 22113132211133213 |
5 | 140244103441403 |
6 | 5040314352155 |
7 | 542562406652 |
oct | 122736453747 |
9 | 31652466518 |
10 | 11131312103 |
11 | 47a237659a |
12 | 21a7a2b65b |
13 | 10851b2412 |
14 | 7784d2899 |
15 | 45237b838 |
hex | 2977a57e7 |
11131312103 has 2 divisors, whose sum is σ = 11131312104. Its totient is φ = 11131312102.
The previous prime is 11131312099. The next prime is 11131312117. The reversal of 11131312103 is 30121313111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11131312103 - 22 = 11131312099 is a prime.
It is a super-2 number, since 2×111313121032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131312123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565656051 + 5565656052.
It is an arithmetic number, because the mean of its divisors is an integer number (5565656052).
Almost surely, 211131312103 is an apocalyptic number.
11131312103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131312103 is an equidigital number, since it uses as much as digits as its factorization.
11131312103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11131312103 its reverse (30121313111), we get a palindrome (41252625214).
The spelling of 11131312103 in words is "eleven billion, one hundred thirty-one million, three hundred twelve thousand, one hundred three".
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