1113133102181 has 2 divisors, whose sum is σ = 1113133102182. Its totient is φ = 1113133102180.

The previous prime is 1113133102139. The next prime is 1113133102187. The reversal of 1113133102181 is 1812013313111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 616060161025 + 497072941156 = 784895^2 + 705034^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113133102181 - 2¹⁴ = 1113133085797 is a prime.

It is a super-4 number, since 4×1113133102181⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1113133102181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113133102187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556566551090 + 556566551091.

It is an arithmetic number, because the mean of its divisors is an integer number (556566551091).

Almost surely, 2^{1113133102181} is an apocalyptic number.

It is an amenable number.

1113133102181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113133102181 is an equidigital number, since it uses as much as digits as its factorization.

1113133102181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 26.

Adding to 1113133102181 its reverse (1812013313111), we get a palindrome (2925146415292).

The spelling of 1113133102181 in words is "one trillion, one hundred thirteen billion, one hundred thirty-three million, one hundred two thousand, one hundred eighty-one".