Base | Representation |
---|---|
bin | 10000001100101011111… |
… | …101010001001100101001 |
3 | 10221102012020000122222011 |
4 | 100030223331101030221 |
5 | 121214144301324202 |
6 | 2211211112555521 |
7 | 143264332660216 |
oct | 20145375211451 |
9 | 3842166018864 |
10 | 1113134011177 |
11 | 39a094147a91 |
12 | 15b8963b2ba1 |
13 | 80c77b6b416 |
14 | 3bc39958b0d |
15 | 1de4da74bd7 |
hex | 1032bf51329 |
1113134011177 has 2 divisors, whose sum is σ = 1113134011178. Its totient is φ = 1113134011176.
The previous prime is 1113134011159. The next prime is 1113134011243. The reversal of 1113134011177 is 7711104313111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 859275234841 + 253858776336 = 926971^2 + 503844^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113134011177 - 215 = 1113133978409 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113134011117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556567005588 + 556567005589.
It is an arithmetic number, because the mean of its divisors is an integer number (556567005589).
Almost surely, 21113134011177 is an apocalyptic number.
It is an amenable number.
1113134011177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113134011177 is an equidigital number, since it uses as much as digits as its factorization.
1113134011177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1764, while the sum is 31.
Adding to 1113134011177 its reverse (7711104313111), we get a palindrome (8824238324288).
The spelling of 1113134011177 in words is "one trillion, one hundred thirteen billion, one hundred thirty-four million, eleven thousand, one hundred seventy-seven".
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