11131341433 has 2 divisors, whose sum is σ = 11131341434. Its totient is φ = 11131341432.

The previous prime is 11131341391. The next prime is 11131341437. The reversal of 11131341433 is 33414313111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9944676729 + 1186664704 = 99723^2 + 34448^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11131341433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11131341398 and 11131341407.

It is not a weakly prime, because it can be changed into another prime (11131341437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565670716 + 5565670717.

It is an arithmetic number, because the mean of its divisors is an integer number (5565670717).

Almost surely, 2^11131341433 is an apocalyptic number.

It is an amenable number.

11131341433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131341433 is an equidigital number, since it uses as much as digits as its factorization.

11131341433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 25.

Adding to 11131341433 its reverse (33414313111), we get a palindrome (44545654544).

The spelling of 11131341433 in words is "eleven billion, one hundred thirty-one million, three hundred forty-one thousand, four hundred thirty-three".