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11131420134217 is a prime number
BaseRepresentation
bin1010000111111011110001…
…0101111100101101001001
31110102011010210211012211211
42201332330111330231021
52424334122023243332
635401412005053121
72226134652661555
oct241767425745511
943364123735754
1011131420134217
113601899519989
1212b94160b71a1
136298c45a6896
142a6a994b4865
1514484903d447
hexa1fbc57cb49

11131420134217 has 2 divisors, whose sum is σ = 11131420134218. Its totient is φ = 11131420134216.

The previous prime is 11131420134209. The next prime is 11131420134223. The reversal of 11131420134217 is 71243102413111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9818972658576 + 1312447475641 = 3133524^2 + 1145621^2 .

It is a cyclic number.

It is not a de Polignac number, because 11131420134217 - 23 = 11131420134209 is a prime.

It is a super-2 number, since 2×111314201342172 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11131420134277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565710067108 + 5565710067109.

It is an arithmetic number, because the mean of its divisors is an integer number (5565710067109).

Almost surely, 211131420134217 is an apocalyptic number.

It is an amenable number.

11131420134217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131420134217 is an equidigital number, since it uses as much as digits as its factorization.

11131420134217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 11131420134217 its reverse (71243102413111), we get a palindrome (82374522547328).

The spelling of 11131420134217 in words is "eleven trillion, one hundred thirty-one billion, four hundred twenty million, one hundred thirty-four thousand, two hundred seventeen".