Base | Representation |
---|---|
bin | 1010000111111011110001… |
… | …0101111100101101001111 |
3 | 1110102011010210211012212001 |
4 | 2201332330111330231033 |
5 | 2424334122023243343 |
6 | 35401412005053131 |
7 | 2226134652661564 |
oct | 241767425745517 |
9 | 43364123735761 |
10 | 11131420134223 |
11 | 3601899519994 |
12 | 12b94160b71a7 |
13 | 6298c45a689c |
14 | 2a6a994b486b |
15 | 14484903d44d |
hex | a1fbc57cb4f |
11131420134223 has 2 divisors, whose sum is σ = 11131420134224. Its totient is φ = 11131420134222.
The previous prime is 11131420134217. The next prime is 11131420134277. The reversal of 11131420134223 is 32243102413111.
It is a weak prime.
It is an emirp because it is prime and its reverse (32243102413111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11131420134223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11131420134191 and 11131420134200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131420134323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565710067111 + 5565710067112.
It is an arithmetic number, because the mean of its divisors is an integer number (5565710067112).
Almost surely, 211131420134223 is an apocalyptic number.
11131420134223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131420134223 is an equidigital number, since it uses as much as digits as its factorization.
11131420134223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 11131420134223 its reverse (32243102413111), we get a palindrome (43374522547334).
The spelling of 11131420134223 in words is "eleven trillion, one hundred thirty-one billion, four hundred twenty million, one hundred thirty-four thousand, two hundred twenty-three".
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