Base | Representation |
---|---|
bin | 10000001100101101001… |
… | …101110001100101010000 |
3 | 10221102020200201212102222 |
4 | 100030231031301211100 |
5 | 121214220202142334 |
6 | 2211213145200212 |
7 | 143265010235336 |
oct | 20145515614520 |
9 | 3842220655388 |
10 | 1113155115344 |
11 | 39a0a5051948 |
12 | 15b8a1490068 |
13 | 80c7c34a2ac |
14 | 3bc3c68db56 |
15 | 1de50842d2e |
hex | 1032d371950 |
1113155115344 has 10 divisors (see below), whose sum is σ = 2156738036010. Its totient is φ = 556577557664.
The previous prime is 1113155115343. The next prime is 1113155115349. The reversal of 1113155115344 is 4435115513111.
It can be written as a sum of positive squares in only one way, i.e., 1070372329744 + 42782785600 = 1034588^2 + 206840^2 .
It is a super-2 number, since 2×11131551153442 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113155115341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34786097339 + ... + 34786097370.
It is an arithmetic number, because the mean of its divisors is an integer number (215673803601).
Almost surely, 21113155115344 is an apocalyptic number.
It is an amenable number.
1113155115344 is a deficient number, since it is larger than the sum of its proper divisors (1043582920666).
1113155115344 is an equidigital number, since it uses as much as digits as its factorization.
1113155115344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69572194717 (or 69572194711 counting only the distinct ones).
The product of its digits is 18000, while the sum is 35.
The spelling of 1113155115344 in words is "one trillion, one hundred thirteen billion, one hundred fifty-five million, one hundred fifteen thousand, three hundred forty-four".
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