Base | Representation |
---|---|
bin | 110011110101100110… |
… | …0010011110010101001 |
3 | 101122100002022201100021 |
4 | 1213223030103302221 |
5 | 3310440413224303 |
6 | 123050103040441 |
7 | 11020420566112 |
oct | 1475314236251 |
9 | 348302281307 |
10 | 111320054953 |
11 | 432352a5a18 |
12 | 196a8a40121 |
13 | a660b37303 |
14 | 5560645209 |
15 | 2d67e49ebd |
hex | 19eb313ca9 |
111320054953 has 2 divisors, whose sum is σ = 111320054954. Its totient is φ = 111320054952.
The previous prime is 111320054927. The next prime is 111320054981. The reversal of 111320054953 is 359450023111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72763983504 + 38556071449 = 269748^2 + 196357^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111320054953 is a prime.
It is not a weakly prime, because it can be changed into another prime (111320094953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55660027476 + 55660027477.
It is an arithmetic number, because the mean of its divisors is an integer number (55660027477).
Almost surely, 2111320054953 is an apocalyptic number.
It is an amenable number.
111320054953 is a deficient number, since it is larger than the sum of its proper divisors (1).
111320054953 is an equidigital number, since it uses as much as digits as its factorization.
111320054953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 111320054953 in words is "one hundred eleven billion, three hundred twenty million, fifty-four thousand, nine hundred fifty-three".
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