Base | Representation |
---|---|
bin | 10000001100110000000… |
… | …101100101011010011001 |
3 | 10221102101001101220100121 |
4 | 100030300011211122121 |
5 | 121214320021044433 |
6 | 2211222030033241 |
7 | 143266133632351 |
oct | 20146005453231 |
9 | 3842331356317 |
10 | 1113203299993 |
11 | 39a11a272774 |
12 | 15b8b5648821 |
13 | 80c8931b315 |
14 | 3bc44c33b61 |
15 | 1de54baec2d |
hex | 10330165699 |
1113203299993 has 2 divisors, whose sum is σ = 1113203299994. Its totient is φ = 1113203299992.
The previous prime is 1113203299979. The next prime is 1113203300023. The reversal of 1113203299993 is 3999923023111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1112292950409 + 910349584 = 1054653^2 + 30172^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113203299993 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1113203299993.
It is not a weakly prime, because it can be changed into another prime (1113203296993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556601649996 + 556601649997.
It is an arithmetic number, because the mean of its divisors is an integer number (556601649997).
Almost surely, 21113203299993 is an apocalyptic number.
It is an amenable number.
1113203299993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113203299993 is an equidigital number, since it uses as much as digits as its factorization.
1113203299993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 708588, while the sum is 52.
The spelling of 1113203299993 in words is "one trillion, one hundred thirteen billion, two hundred three million, two hundred ninety-nine thousand, nine hundred ninety-three".
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