Base | Representation |
---|---|
bin | 10100101111000010… |
… | …11011010010110001 |
3 | 1001201210221002001021 |
4 | 22113201123102301 |
5 | 140244301304003 |
6 | 5040342335441 |
7 | 542601630646 |
oct | 122741332261 |
9 | 31653832037 |
10 | 11132056753 |
11 | 47a2835004 |
12 | 21a812a581 |
13 | 10853b333c |
14 | 778647dcd |
15 | 4524772bd |
hex | 29785b4b1 |
11132056753 has 2 divisors, whose sum is σ = 11132056754. Its totient is φ = 11132056752.
The previous prime is 11132056717. The next prime is 11132056759. The reversal of 11132056753 is 35765023111.
11132056753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11065356864 + 66699889 = 105192^2 + 8167^2 .
It is a cyclic number.
It is not a de Polignac number, because 11132056753 - 217 = 11131925681 is a prime.
It is not a weakly prime, because it can be changed into another prime (11132056759) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566028376 + 5566028377.
It is an arithmetic number, because the mean of its divisors is an integer number (5566028377).
Almost surely, 211132056753 is an apocalyptic number.
It is an amenable number.
11132056753 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132056753 is an equidigital number, since it uses as much as digits as its factorization.
11132056753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18900, while the sum is 34.
Adding to 11132056753 its reverse (35765023111), we get a palindrome (46897079864).
The spelling of 11132056753 in words is "eleven billion, one hundred thirty-two million, fifty-six thousand, seven hundred fifty-three".
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