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11132142213431 is a prime number
BaseRepresentation
bin1010000111111110011101…
…1000011101100100110111
31110102020000010112122022102
42201333213120131210313
52424342111401312211
635402011401452315
72226161601362021
oct241774730354467
943366003478272
1011132142213431
11360212a079768
1212b9597aa109b
136299ab0768a5
142a6b27359011
1514488c622a3b
hexa1fe761d937

11132142213431 has 2 divisors, whose sum is σ = 11132142213432. Its totient is φ = 11132142213430.

The previous prime is 11132142213407. The next prime is 11132142213457. The reversal of 11132142213431 is 13431224123111.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11132142213431 is a prime.

It is a super-2 number, since 2×111321422134312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11132142213394 and 11132142213403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132142213481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566071106715 + 5566071106716.

It is an arithmetic number, because the mean of its divisors is an integer number (5566071106716).

Almost surely, 211132142213431 is an apocalyptic number.

11132142213431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132142213431 is an equidigital number, since it uses as much as digits as its factorization.

11132142213431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456, while the sum is 29.

Adding to 11132142213431 its reverse (13431224123111), we get a palindrome (24563366336542).

The spelling of 11132142213431 in words is "eleven trillion, one hundred thirty-two billion, one hundred forty-two million, two hundred thirteen thousand, four hundred thirty-one".