Base | Representation |
---|---|
bin | 1010000111111111000011… |
… | …0010010111101100011111 |
3 | 1110102020102010110000211120 |
4 | 2201333300302113230133 |
5 | 2424342422300000111 |
6 | 35402035155422023 |
7 | 2226165525502200 |
oct | 241776062275437 |
9 | 43366363400746 |
10 | 11132300000031 |
11 | 360220014a111 |
12 | 12b96208b4913 |
13 | 629a04970a42 |
14 | 2a6b402ad5a7 |
15 | 14489b3de406 |
hex | a1ff0c97b1f |
11132300000031 has 48 divisors (see below), whose sum is σ = 17710276428000. Its totient is φ = 6199400992512.
The previous prime is 11132299999999. The next prime is 11132300000057. The reversal of 11132300000031 is 13000000323111.
It is not a de Polignac number, because 11132300000031 - 25 = 11132299999999 is a prime.
It is a super-2 number, since 2×111323000000312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11132300000831) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3633996 + ... + 5955713.
It is an arithmetic number, because the mean of its divisors is an integer number (368964092250).
Almost surely, 211132300000031 is an apocalyptic number.
11132300000031 is a deficient number, since it is larger than the sum of its proper divisors (6577976427969).
11132300000031 is a wasteful number, since it uses less digits than its factorization.
11132300000031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9589928 (or 9589921 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 11132300000031 its reverse (13000000323111), we get a palindrome (24132300323142).
The spelling of 11132300000031 in words is "eleven trillion, one hundred thirty-two billion, three hundred million, thirty-one", and thus it is an aban number.
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