Base | Representation |
---|---|
bin | 1010000111111111000101… |
… | …1001010100010111100011 |
3 | 1110102020102211122202022021 |
4 | 2201333301121110113203 |
5 | 2424342432403210034 |
6 | 35402040202322311 |
7 | 2226166011335005 |
oct | 241776131242743 |
9 | 43366384582267 |
10 | 11132310210019 |
11 | 3602205993019 |
12 | 12b96241b9397 |
13 | 629a06b0705b |
14 | 2a6b417aa375 |
15 | 14489c2596b4 |
hex | a1ff16545e3 |
11132310210019 has 2 divisors, whose sum is σ = 11132310210020. Its totient is φ = 11132310210018.
The previous prime is 11132310209903. The next prime is 11132310210023. The reversal of 11132310210019 is 91001201323111.
It is a strong prime.
It is an emirp because it is prime and its reverse (91001201323111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11132310210019 - 213 = 11132310201827 is a prime.
It is a super-2 number, since 2×111323102100192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11132310209975 and 11132310210002.
It is not a weakly prime, because it can be changed into another prime (11132310213019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566155105009 + 5566155105010.
It is an arithmetic number, because the mean of its divisors is an integer number (5566155105010).
Almost surely, 211132310210019 is an apocalyptic number.
11132310210019 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132310210019 is an equidigital number, since it uses as much as digits as its factorization.
11132310210019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 11132310210019 in words is "eleven trillion, one hundred thirty-two billion, three hundred ten million, two hundred ten thousand, nineteen".
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