Base | Representation |
---|---|
bin | 10000001100110001101… |
… | …111110000001001011111 |
3 | 10221102102222202212122012 |
4 | 100030301233300021133 |
5 | 121214344132144411 |
6 | 2211224502341435 |
7 | 143266622326112 |
oct | 20146157601137 |
9 | 3842388685565 |
10 | 1113231131231 |
11 | 39a133a5179a |
12 | 15b902a2a87b |
13 | 80c920140cb |
14 | 3bc487da579 |
15 | 1de5735b18b |
hex | 10331bf025f |
1113231131231 has 2 divisors, whose sum is σ = 1113231131232. Its totient is φ = 1113231131230.
The previous prime is 1113231131183. The next prime is 1113231131261. The reversal of 1113231131231 is 1321311323111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113231131231 - 226 = 1113164022367 is a prime.
It is a super-2 number, since 2×11132311312312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113231131197 and 1113231131206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113231131261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556615565615 + 556615565616.
It is an arithmetic number, because the mean of its divisors is an integer number (556615565616).
Almost surely, 21113231131231 is an apocalyptic number.
1113231131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113231131231 is an equidigital number, since it uses as much as digits as its factorization.
1113231131231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 324, while the sum is 23.
Adding to 1113231131231 its reverse (1321311323111), we get a palindrome (2434542454342).
The spelling of 1113231131231 in words is "one trillion, one hundred thirteen billion, two hundred thirty-one million, one hundred thirty-one thousand, two hundred thirty-one".
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