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11132320244141 is a prime number
BaseRepresentation
bin1010000111111111000111…
…1111100110000110101101
31110102020110112112112112102
42201333301333212012231
52424342442440303031
635402041201344445
72226166162536005
oct241776177460655
943366415475472
1011132320244141
113602210616888
1212b9627638125
13629a08c0b2c5
142a6b42c5d005
1514489d08c7cb
hexa1ff1fe61ad

11132320244141 has 2 divisors, whose sum is σ = 11132320244142. Its totient is φ = 11132320244140.

The previous prime is 11132320244131. The next prime is 11132320244179. The reversal of 11132320244141 is 14144202323111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7811069139241 + 3321251104900 = 2794829^2 + 1822430^2 .

It is a cyclic number.

It is not a de Polignac number, because 11132320244141 - 26 = 11132320244077 is a prime.

It is a super-2 number, since 2×111323202441412 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11132320244131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566160122070 + 5566160122071.

It is an arithmetic number, because the mean of its divisors is an integer number (5566160122071).

Almost surely, 211132320244141 is an apocalyptic number.

It is an amenable number.

11132320244141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132320244141 is an equidigital number, since it uses as much as digits as its factorization.

11132320244141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 11132320244141 its reverse (14144202323111), we get a palindrome (25276522567252).

The spelling of 11132320244141 in words is "eleven trillion, one hundred thirty-two billion, three hundred twenty million, two hundred forty-four thousand, one hundred forty-one".