111324243345251 has 2 divisors, whose sum is σ = 111324243345252. Its totient is φ = 111324243345250.

The previous prime is 111324243345229. The next prime is 111324243345253. The reversal of 111324243345251 is 152543342423111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111324243345251 - 2²⁶ = 111324176236387 is a prime.

Together with 111324243345253, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 111324243345199 and 111324243345208.

It is not a weakly prime, because it can be changed into another prime (111324243345253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55662121672625 + 55662121672626.

It is an arithmetic number, because the mean of its divisors is an integer number (55662121672626).

Almost surely, 2^{111324243345251} is an apocalyptic number.

111324243345251 is a deficient number, since it is larger than the sum of its proper divisors (1).

111324243345251 is an equidigital number, since it uses as much as digits as its factorization.

111324243345251 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 345600, while the sum is 41.

Adding to 111324243345251 its reverse (152543342423111), we get a palindrome (263867585768362).

The spelling of 111324243345251 in words is "one hundred eleven trillion, three hundred twenty-four billion, two hundred forty-three million, three hundred forty-five thousand, two hundred fifty-one".