Base | Representation |
---|---|
bin | 11001010100000100010000… |
… | …011001101000011011111100 |
3 | 112121012001111122120110000001 |
4 | 121110010100121220123330 |
5 | 104043013042320344200 |
6 | 1032440204023444044 |
7 | 32310223134620350 |
oct | 3124042031503374 |
9 | 477161448513001 |
10 | 111330122434300 |
11 | 32522926820090 |
12 | 105a06348b6624 |
13 | 4a17501c2a903 |
14 | 1d6c599cc5460 |
15 | cd0e42d9876a |
hex | 6541106686fc |
111330122434300 has 576 divisors, whose sum is σ = 309128414515200. Its totient is φ = 33798900326400.
The previous prime is 111330122434291. The next prime is 111330122434369. The reversal of 111330122434300 is 3434221033111.
It is a super-2 number, since 2×1113301224343002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 26139965571 + ... + 26139969829.
It is an arithmetic number, because the mean of its divisors is an integer number (536681275200).
Almost surely, 2111330122434300 is an apocalyptic number.
111330122434300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111330122434300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (154564207257600).
111330122434300 is an abundant number, since it is smaller than the sum of its proper divisors (197798292080900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111330122434300 is a wasteful number, since it uses less digits than its factorization.
111330122434300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4866 (or 4859 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 111330122434300 its reverse (3434221033111), we get a palindrome (114764343467411).
The spelling of 111330122434300 in words is "one hundred eleven trillion, three hundred thirty billion, one hundred twenty-two million, four hundred thirty-four thousand, three hundred".
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