Base | Representation |
---|---|
bin | 110011110101111011… |
… | …0000100001010100001 |
3 | 101122100211220211111011 |
4 | 1213223312010022201 |
5 | 3311001214012433 |
6 | 123051133420521 |
7 | 11020612615552 |
oct | 1475366041241 |
9 | 348324824434 |
10 | 111331000993 |
11 | 432404a1933 |
12 | 196b063a741 |
13 | a66319a664 |
14 | 5561c94329 |
15 | 2d68dad3cd |
hex | 19ebd842a1 |
111331000993 has 2 divisors, whose sum is σ = 111331000994. Its totient is φ = 111331000992.
The previous prime is 111331000931. The next prime is 111331001071. The reversal of 111331000993 is 399000133111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102804879424 + 8526121569 = 320632^2 + 92337^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111331000993 is a prime.
It is not a weakly prime, because it can be changed into another prime (111331006993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55665500496 + 55665500497.
It is an arithmetic number, because the mean of its divisors is an integer number (55665500497).
Almost surely, 2111331000993 is an apocalyptic number.
It is an amenable number.
111331000993 is a deficient number, since it is larger than the sum of its proper divisors (1).
111331000993 is an equidigital number, since it uses as much as digits as its factorization.
111331000993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 31.
The spelling of 111331000993 in words is "one hundred eleven billion, three hundred thirty-one million, nine hundred ninety-three", and thus it is an aban number.
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