1113312121333 has 4 divisors (see below), whose sum is σ = 1171907496160. Its totient is φ = 1054716746508.

The previous prime is 1113312121301. The next prime is 1113312121463. The reversal of 1113312121333 is 3331212133111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113312121333 - 2⁵ = 1113312121301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113312121298 and 1113312121307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113312161333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29297687385 + ... + 29297687422.

It is an arithmetic number, because the mean of its divisors is an integer number (292976874040).

Almost surely, 2^{1113312121333} is an apocalyptic number.

It is an amenable number.

1113312121333 is a deficient number, since it is larger than the sum of its proper divisors (58595374827).

1113312121333 is an equidigital number, since it uses as much as digits as its factorization.

1113312121333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58595374826.

The product of its digits is 972, while the sum is 25.

Adding to 1113312121333 its reverse (3331212133111), we get a palindrome (4444524254444).

The spelling of 1113312121333 in words is "one trillion, one hundred thirteen billion, three hundred twelve million, one hundred twenty-one thousand, three hundred thirty-three".