1113313002001 has 2 divisors, whose sum is σ = 1113313002002. Its totient is φ = 1113313002000.

The previous prime is 1113313001951. The next prime is 1113313002017. The reversal of 1113313002001 is 1002003133111.

It is an a-pointer prime, because the next prime (1113313002017) can be obtained adding 1113313002001 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1042034681601 + 71278320400 = 1020801^2 + 266980^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113313002001 - 2¹³ = 1113312993809 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113313000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656501000 + 556656501001.

It is an arithmetic number, because the mean of its divisors is an integer number (556656501001).

Almost surely, 2^{1113313002001} is an apocalyptic number.

It is an amenable number.

1113313002001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113313002001 is an equidigital number, since it uses as much as digits as its factorization.

1113313002001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1113313002001 its reverse (1002003133111), we get a palindrome (2115316135112).

The spelling of 1113313002001 in words is "one trillion, one hundred thirteen billion, three hundred thirteen million, two thousand, one".