Base | Representation |
---|---|
bin | 10000001100110110101… |
… | …000000110100110110111 |
3 | 10221102122200211212010212 |
4 | 100030312220012212313 |
5 | 121220031112342101 |
6 | 2211240545340035 |
7 | 143301635315024 |
oct | 20146650064667 |
9 | 3842580755125 |
10 | 1113313012151 |
11 | 39a17619807a |
12 | 15b92633761b |
13 | 80ca5c82662 |
14 | 3bc5563254b |
15 | 1de5e6321bb |
hex | 10336a069b7 |
1113313012151 has 2 divisors, whose sum is σ = 1113313012152. Its totient is φ = 1113313012150.
The previous prime is 1113313012111. The next prime is 1113313012157. The reversal of 1113313012151 is 1512103133111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113313012151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113313012157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656506075 + 556656506076.
It is an arithmetic number, because the mean of its divisors is an integer number (556656506076).
Almost surely, 21113313012151 is an apocalyptic number.
1113313012151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113313012151 is an equidigital number, since it uses as much as digits as its factorization.
1113313012151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270, while the sum is 23.
Adding to 1113313012151 its reverse (1512103133111), we get a palindrome (2625416145262).
The spelling of 1113313012151 in words is "one trillion, one hundred thirteen billion, three hundred thirteen million, twelve thousand, one hundred fifty-one".
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