Base | Representation |
---|---|
bin | 10000001100110110101… |
… | …000101101000010000111 |
3 | 10221102122201010212001012 |
4 | 100030312220231002013 |
5 | 121220031132411133 |
6 | 2211240552552435 |
7 | 143301636541631 |
oct | 20146650550207 |
9 | 3842581125035 |
10 | 1113313169543 |
11 | 39a176295353 |
12 | 15b9263b271b |
13 | 80ca60091a3 |
14 | 3bc55673a51 |
15 | 1de5e663b48 |
hex | 10336a2d087 |
1113313169543 has 2 divisors, whose sum is σ = 1113313169544. Its totient is φ = 1113313169542.
The previous prime is 1113313169533. The next prime is 1113313169599. The reversal of 1113313169543 is 3459613133111.
It is a weak prime.
It is an emirp because it is prime and its reverse (3459613133111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113313169543 - 232 = 1109018202247 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1113313169543.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113313169533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656584771 + 556656584772.
It is an arithmetic number, because the mean of its divisors is an integer number (556656584772).
Almost surely, 21113313169543 is an apocalyptic number.
1113313169543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113313169543 is an equidigital number, since it uses as much as digits as its factorization.
1113313169543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 87480, while the sum is 41.
The spelling of 1113313169543 in words is "one trillion, one hundred thirteen billion, three hundred thirteen million, one hundred sixty-nine thousand, five hundred forty-three".
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