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11133133103 is a prime number
BaseRepresentation
bin10100101111001011…
…00010000100101111
31001201212221202112002
422113211202010233
5140300040224403
65040421402515
7542614033001
oct122745420457
931655852462
1011133133103
1147a33aa754
1221a856943b
13108569c231
14778848371
154525db188
hex29796212f

11133133103 has 2 divisors, whose sum is σ = 11133133104. Its totient is φ = 11133133102.

The previous prime is 11133133097. The next prime is 11133133127. The reversal of 11133133103 is 30133133111.

11133133103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11133133103 - 210 = 11133132079 is a prime.

It is a super-2 number, since 2×111331331032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11133133903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566566551 + 5566566552.

It is an arithmetic number, because the mean of its divisors is an integer number (5566566552).

Almost surely, 211133133103 is an apocalyptic number.

11133133103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133133103 is an equidigital number, since it uses as much as digits as its factorization.

11133133103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 11133133103 its reverse (30133133111), we get a palindrome (41266266214).

The spelling of 11133133103 in words is "eleven billion, one hundred thirty-three million, one hundred thirty-three thousand, one hundred three".