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111332099999977 is a prime number
BaseRepresentation
bin11001010100000110000110…
…010001011100100011101001
3112121012020121110201012010021
4121110012012101130203221
5104043031120044444402
61032441132145520441
732310323136634063
oct3124060621344351
9477166543635107
10111332099999977
113252375103448a
12105a0aa7043121
134a1775884b80c
141d6c7067c0733
15cd100b7c8d37
hex65418645c8e9

111332099999977 has 2 divisors, whose sum is σ = 111332099999978. Its totient is φ = 111332099999976.

The previous prime is 111332099999933. The next prime is 111332100000053. The reversal of 111332099999977 is 779999990233111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96301622328921 + 15030477671056 = 9813339^2 + 3876916^2 .

It is an emirp because it is prime and its reverse (779999990233111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111332099999977 - 223 = 111332091611369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111332099999897 and 111332099999906.

It is not a weakly prime, because it can be changed into another prime (111332099994977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55666049999988 + 55666049999989.

It is an arithmetic number, because the mean of its divisors is an integer number (55666049999989).

Almost surely, 2111332099999977 is an apocalyptic number.

It is an amenable number.

111332099999977 is a deficient number, since it is larger than the sum of its proper divisors (1).

111332099999977 is an equidigital number, since it uses as much as digits as its factorization.

111332099999977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 468730962, while the sum is 79.

The spelling of 111332099999977 in words is "one hundred eleven trillion, three hundred thirty-two billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred seventy-seven".