111332100000053 has 2 divisors, whose sum is σ = 111332100000054. Its totient is φ = 111332100000052.

The previous prime is 111332099999977. The next prime is 111332100000097. The reversal of 111332100000053 is 350000001233111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100174616160529 + 11157483839524 = 10008727^2 + 3340282^2 .

It is an emirp because it is prime and its reverse (350000001233111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111332100000053 - 2¹⁴ = 111332099983669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111332099999980 and 111332100000034.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111332100005053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55666050000026 + 55666050000027.

It is an arithmetic number, because the mean of its divisors is an integer number (55666050000027).

Almost surely, 2^{111332100000053} is an apocalyptic number.

It is an amenable number.

111332100000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

111332100000053 is an equidigital number, since it uses as much as digits as its factorization.

111332100000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 111332100000053 its reverse (350000001233111), we get a palindrome (461332101233164).

The spelling of 111332100000053 in words is "one hundred eleven trillion, three hundred thirty-two billion, one hundred million, fifty-three", and thus it is an aban number.