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1113322120973 is a prime number
BaseRepresentation
bin10000001100110111001…
…010110110011100001101
310221102200022222122002122
4100030313022312130031
5121220040430332343
62211241512502325
7143302105613246
oct20146712663415
93842608878078
101113322120973
1139a180349727
1215b9293aa9a5
1380ca7b216aa
143bc56923ccd
151de60331068
hex103372b670d

1113322120973 has 2 divisors, whose sum is σ = 1113322120974. Its totient is φ = 1113322120972.

The previous prime is 1113322120949. The next prime is 1113322120991. The reversal of 1113322120973 is 3790212233111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 976068913444 + 137253207529 = 987962^2 + 370477^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113322120973 - 212 = 1113322116877 is a prime.

It is a super-2 number, since 2×11133221209732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113322120903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556661060486 + 556661060487.

It is an arithmetic number, because the mean of its divisors is an integer number (556661060487).

Almost surely, 21113322120973 is an apocalyptic number.

It is an amenable number.

1113322120973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113322120973 is an equidigital number, since it uses as much as digits as its factorization.

1113322120973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 35.

The spelling of 1113322120973 in words is "one trillion, one hundred thirteen billion, three hundred twenty-two million, one hundred twenty thousand, nine hundred seventy-three".