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11133310130 = 252694138777
BaseRepresentation
bin10100101111001100…
…01101010010110010
31001201220021202100122
422113212031102302
5140300111411010
65040425250242
7542615401055
oct122746152262
931656252318
1011133310130
1147a3510758
1221a8633982
131085731997
14778892a9c
15452623855
hex29798d4b2

11133310130 has 16 divisors (see below), whose sum is σ = 20114461080. Its totient is φ = 4436767872.

The previous prime is 11133310117. The next prime is 11133310169. The reversal of 11133310130 is 3101333111.

11133310130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 5484735481 + 5648574649 = 74059^2 + 75157^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11133310099 and 11133310108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2066699 + ... + 2072078.

Almost surely, 211133310130 is an apocalyptic number.

11133310130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11133310130 is a deficient number, since it is larger than the sum of its proper divisors (8981150950).

11133310130 is a wasteful number, since it uses less digits than its factorization.

11133310130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4139053.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 11133310130 its reverse (3101333111), we get a palindrome (14234643241).

The spelling of 11133310130 in words is "eleven billion, one hundred thirty-three million, three hundred ten thousand, one hundred thirty".

Divisors: 1 2 5 10 269 538 1345 2690 4138777 8277554 20693885 41387770 1113331013 2226662026 5566655065 11133310130