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11133314134 = 237150450191
BaseRepresentation
bin10100101111001100…
…01110010001010110
31001201220021221211221
422113212032101112
5140300112023014
65040425320554
7542615415535
oct122746162126
931656257757
1011133314134
1147a3513768
1221a863615a
131085733757
1477889431c
15452624b24
hex29798e456

11133314134 has 8 divisors (see below), whose sum is σ = 17151321888. Its totient is φ = 5416206840.

The previous prime is 11133314131. The next prime is 11133314189. The reversal of 11133314134 is 43141333111.

11133314134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11133314099 and 11133314108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11133314131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75225022 + ... + 75225169.

It is an arithmetic number, because the mean of its divisors is an integer number (2143915236).

Almost surely, 211133314134 is an apocalyptic number.

11133314134 is a deficient number, since it is larger than the sum of its proper divisors (6018007754).

11133314134 is a wasteful number, since it uses less digits than its factorization.

11133314134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150450230.

The product of its digits is 1296, while the sum is 25.

Adding to 11133314134 its reverse (43141333111), we get a palindrome (54274647245).

The spelling of 11133314134 in words is "eleven billion, one hundred thirty-three million, three hundred fourteen thousand, one hundred thirty-four".

Divisors: 1 2 37 74 150450191 300900382 5566657067 11133314134