Base | Representation |
---|---|
bin | 1010001000000010110110… |
… | …1001010001001011111101 |
3 | 1110102100001021200102202111 |
4 | 2202000231221101023331 |
5 | 2424402020140234003 |
6 | 35402324351454021 |
7 | 2226233034166201 |
oct | 242005551211375 |
9 | 43370037612674 |
10 | 11133321024253 |
11 | 360268452278a |
12 | 12b9866827311 |
13 | 629b3835c59c |
14 | 2a6bd9b30b01 |
15 | 14490ad74e6d |
hex | a202da512fd |
11133321024253 has 2 divisors, whose sum is σ = 11133321024254. Its totient is φ = 11133321024252.
The previous prime is 11133321024247. The next prime is 11133321024337. The reversal of 11133321024253 is 35242012333111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8900753128569 + 2232567895684 = 2983413^2 + 1494178^2 .
It is a cyclic number.
It is not a de Polignac number, because 11133321024253 - 213 = 11133321016061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133321024233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566660512126 + 5566660512127.
It is an arithmetic number, because the mean of its divisors is an integer number (5566660512127).
Almost surely, 211133321024253 is an apocalyptic number.
It is an amenable number.
11133321024253 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133321024253 is an equidigital number, since it uses as much as digits as its factorization.
11133321024253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 11133321024253 its reverse (35242012333111), we get a palindrome (46375333357364).
The spelling of 11133321024253 in words is "eleven trillion, one hundred thirty-three billion, three hundred twenty-one million, twenty-four thousand, two hundred fifty-three".
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