Base | Representation |
---|---|
bin | 1010001000000010111000… |
… | …1100110010000101001111 |
3 | 1110102100001221012102101002 |
4 | 2202000232030302011033 |
5 | 2424402030031142111 |
6 | 35402325323210515 |
7 | 2226233206262333 |
oct | 242005614620517 |
9 | 43370057172332 |
10 | 11133330334031 |
11 | 3602689801314 |
12 | 12b9869976a3b |
13 | 629b3a26bc29 |
14 | 2a6bdb0757c3 |
15 | 14490bab363b |
hex | a202e33214f |
11133330334031 has 2 divisors, whose sum is σ = 11133330334032. Its totient is φ = 11133330334030.
The previous prime is 11133330333997. The next prime is 11133330334039. The reversal of 11133330334031 is 13043303333111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11133330334031 - 234 = 11116150464847 is a prime.
It is a super-2 number, since 2×111333303340312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11133330333985 and 11133330334003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133330334039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566665167015 + 5566665167016.
It is an arithmetic number, because the mean of its divisors is an integer number (5566665167016).
Almost surely, 211133330334031 is an apocalyptic number.
11133330334031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133330334031 is an equidigital number, since it uses as much as digits as its factorization.
11133330334031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 29.
Adding to 11133330334031 its reverse (13043303333111), we get a palindrome (24176633667142).
The spelling of 11133330334031 in words is "eleven trillion, one hundred thirty-three billion, three hundred thirty million, three hundred thirty-four thousand, thirty-one".
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