Base | Representation |
---|---|
bin | 1010001000000011001110… |
… | …1100000100010100111011 |
3 | 1110102100022100110221100221 |
4 | 2202000303230010110323 |
5 | 2424402222114440212 |
6 | 35402342413040511 |
7 | 2226235405100344 |
oct | 242006354042473 |
9 | 43370270427327 |
10 | 11133422421307 |
11 | 36027267888aa |
12 | 12b9894786137 |
13 | 629b53371c44 |
14 | 2a6c093a70cb |
15 | 144914c03807 |
hex | a2033b0453b |
11133422421307 has 2 divisors, whose sum is σ = 11133422421308. Its totient is φ = 11133422421306.
The previous prime is 11133422421293. The next prime is 11133422421313. The reversal of 11133422421307 is 70312422433111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11133422421307 - 27 = 11133422421179 is a prime.
It is a super-2 number, since 2×111334224213072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11133422421347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566711210653 + 5566711210654.
It is an arithmetic number, because the mean of its divisors is an integer number (5566711210654).
Almost surely, 211133422421307 is an apocalyptic number.
11133422421307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133422421307 is an equidigital number, since it uses as much as digits as its factorization.
11133422421307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 11133422421307 its reverse (70312422433111), we get a palindrome (81445844854418).
The spelling of 11133422421307 in words is "eleven trillion, one hundred thirty-three billion, four hundred twenty-two million, four hundred twenty-one thousand, three hundred seven".
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