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1113342428413 is a prime number
BaseRepresentation
bin10000001100111000011…
…000010100010011111101
310221102201202012100200001
4100030320120110103331
5121220111130202123
62211243520034301
7143302443332515
oct20147030242375
93842652170601
101113342428413
1139a190859a36
1215b934162991
1380cac0b1a27
143bc594cc845
151de61ee30ad
hex103386144fd

1113342428413 has 2 divisors, whose sum is σ = 1113342428414. Its totient is φ = 1113342428412.

The previous prime is 1113342428399. The next prime is 1113342428417. The reversal of 1113342428413 is 3148242433111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931761617284 + 181580811129 = 965278^2 + 426123^2 .

It is an emirp because it is prime and its reverse (3148242433111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1113342428413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113342428417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556671214206 + 556671214207.

It is an arithmetic number, because the mean of its divisors is an integer number (556671214207).

Almost surely, 21113342428413 is an apocalyptic number.

It is an amenable number.

1113342428413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113342428413 is an equidigital number, since it uses as much as digits as its factorization.

1113342428413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 55296, while the sum is 37.

The spelling of 1113342428413 in words is "one trillion, one hundred thirteen billion, three hundred forty-two million, four hundred twenty-eight thousand, four hundred thirteen".