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1113343242001 is a prime number
BaseRepresentation
bin10000001100111000011…
…011011010111100010001
310221102201210201200200221
4100030320123122330101
5121220111332221001
62211243545313041
7143302453261504
oct20147033327421
93842653650627
101113343242001
1139a191265221
1215b934495781
1380cac308143
143bc5966113b
151de621041a1
hex103386daf11

1113343242001 has 2 divisors, whose sum is σ = 1113343242002. Its totient is φ = 1113343242000.

The previous prime is 1113343241993. The next prime is 1113343242007. The reversal of 1113343242001 is 1002423433111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 952683363025 + 160659878976 = 976055^2 + 400824^2 .

It is an emirp because it is prime and its reverse (1002423433111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113343242001 - 23 = 1113343241993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1113343242007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556671621000 + 556671621001.

It is an arithmetic number, because the mean of its divisors is an integer number (556671621001).

Almost surely, 21113343242001 is an apocalyptic number.

It is an amenable number.

1113343242001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113343242001 is an equidigital number, since it uses as much as digits as its factorization.

1113343242001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1113343242001 its reverse (1002423433111), we get a palindrome (2115766675112).

The spelling of 1113343242001 in words is "one trillion, one hundred thirteen billion, three hundred forty-three million, two hundred forty-two thousand, one".