1113351142733 has 2 divisors, whose sum is σ = 1113351142734. Its totient is φ = 1113351142732.

The previous prime is 1113351142699. The next prime is 1113351142751. The reversal of 1113351142733 is 3372411533111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1042976072644 + 70375070089 = 1021262^2 + 265283^2 .

It is an emirp because it is prime and its reverse (3372411533111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113351142733 - 2¹² = 1113351138637 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113351142693 and 1113351142702.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113351142753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556675571366 + 556675571367.

It is an arithmetic number, because the mean of its divisors is an integer number (556675571367).

Almost surely, 2^{1113351142733} is an apocalyptic number.

It is an amenable number.

1113351142733 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113351142733 is an equidigital number, since it uses as much as digits as its factorization.

1113351142733 is an evil number, because the sum of its binary digits is even.

The product of its digits is 22680, while the sum is 35.

Adding to 1113351142733 its reverse (3372411533111), we get a palindrome (4485762675844).

The spelling of 1113351142733 in words is "one trillion, one hundred thirteen billion, three hundred fifty-one million, one hundred forty-two thousand, seven hundred thirty-three".