Base | Representation |
---|---|
bin | 10000001100111011111… |
… | …101000101110100011011 |
3 | 10221102212221001020020221 |
4 | 100030323331011310123 |
5 | 121220222003300102 |
6 | 2211253501300511 |
7 | 143304102151051 |
oct | 20147375056433 |
9 | 3842787036227 |
10 | 1113402400027 |
11 | 39a2116a0555 |
12 | 15b950264737 |
13 | 80cbb64baa8 |
14 | 3bc634601d1 |
15 | 1de673dc637 |
hex | 1033bf45d1b |
1113402400027 has 2 divisors, whose sum is σ = 1113402400028. Its totient is φ = 1113402400026.
The previous prime is 1113402399961. The next prime is 1113402400091. The reversal of 1113402400027 is 7200042043111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113402400027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113402399974 and 1113402400010.
It is not a weakly prime, because it can be changed into another prime (1113402400427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556701200013 + 556701200014.
It is an arithmetic number, because the mean of its divisors is an integer number (556701200014).
Almost surely, 21113402400027 is an apocalyptic number.
1113402400027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113402400027 is an equidigital number, since it uses as much as digits as its factorization.
1113402400027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1113402400027 its reverse (7200042043111), we get a palindrome (8313444443138).
The spelling of 1113402400027 in words is "one trillion, one hundred thirteen billion, four hundred two million, four hundred thousand, twenty-seven".
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