Base | Representation |
---|---|
bin | 10000001100111100011… |
… | …101111110100111110101 |
3 | 10221102220112021020102101 |
4 | 100030330131332213311 |
5 | 121220231210140201 |
6 | 2211254410142101 |
7 | 143304235346005 |
oct | 20147435764765 |
9 | 3842815236371 |
10 | 1113411021301 |
11 | 39a216549877 |
12 | 15b953121931 |
13 | 80cc0379c37 |
14 | 3bc64666005 |
15 | 1de68041d01 |
hex | 1033c77e9f5 |
1113411021301 has 2 divisors, whose sum is σ = 1113411021302. Its totient is φ = 1113411021300.
The previous prime is 1113411021271. The next prime is 1113411021347. The reversal of 1113411021301 is 1031201143111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1004906002500 + 108505018801 = 1002450^2 + 329401^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113411021301 - 219 = 1113410497013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113411021901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556705510650 + 556705510651.
It is an arithmetic number, because the mean of its divisors is an integer number (556705510651).
Almost surely, 21113411021301 is an apocalyptic number.
It is an amenable number.
1113411021301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113411021301 is an equidigital number, since it uses as much as digits as its factorization.
1113411021301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 1113411021301 its reverse (1031201143111), we get a palindrome (2144612164412).
The spelling of 1113411021301 in words is "one trillion, one hundred thirteen billion, four hundred eleven million, twenty-one thousand, three hundred one".
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