11134131032021 has 2 divisors, whose sum is σ = 11134131032022. Its totient is φ = 11134131032020.

The previous prime is 11134131031997. The next prime is 11134131032069. The reversal of 11134131032021 is 12023013143111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7865158551121 + 3268972480900 = 2804489^2 + 1808030^2 .

It is a cyclic number.

It is not a de Polignac number, because 11134131032021 - 2¹⁸ = 11134130769877 is a prime.

It is a super-4 number, since 4×11134131032021⁴ (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11134131032821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567065516010 + 5567065516011.

It is an arithmetic number, because the mean of its divisors is an integer number (5567065516011).

Almost surely, 2^{11134131032021} is an apocalyptic number.

It is an amenable number.

11134131032021 is a deficient number, since it is larger than the sum of its proper divisors (1).

11134131032021 is an equidigital number, since it uses as much as digits as its factorization.

11134131032021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11134131032021 its reverse (12023013143111), we get a palindrome (23157144175132).

The spelling of 11134131032021 in words is "eleven trillion, one hundred thirty-four billion, one hundred thirty-one million, thirty-two thousand, twenty-one".