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11134500989 is a prime number
BaseRepresentation
bin10100101111010101…
…10000000001111101
31001201222112020220112
422113222300001331
5140300413012424
65040510555405
7542631461003
oct122752600175
931658466815
1011134500989
1147a4154437
1221a8b08b65
131085a5aa31
14778ac2a73
154527ab60e
hex297ab007d

11134500989 has 2 divisors, whose sum is σ = 11134500990. Its totient is φ = 11134500988.

The previous prime is 11134500943. The next prime is 11134501069. The reversal of 11134500989 is 98900543111.

11134500989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11133415225 + 1085764 = 105515^2 + 1042^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11134500989 is a prime.

It is a super-3 number, since 3×111345009893 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11134500929) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567250494 + 5567250495.

It is an arithmetic number, because the mean of its divisors is an integer number (5567250495).

Almost surely, 211134500989 is an apocalyptic number.

It is an amenable number.

11134500989 is a deficient number, since it is larger than the sum of its proper divisors (1).

11134500989 is an equidigital number, since it uses as much as digits as its factorization.

11134500989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 41.

The spelling of 11134500989 in words is "eleven billion, one hundred thirty-four million, five hundred thousand, nine hundred eighty-nine".