Base | Representation |
---|---|
bin | 10000001100111111101… |
… | …011111011110011100111 |
3 | 10221110001021212012221211 |
4 | 100030333223323303213 |
5 | 121220334020331211 |
6 | 2211304015252251 |
7 | 143305462302433 |
oct | 20147753736347 |
9 | 3843037765854 |
10 | 1113465011431 |
11 | 39a243a75413 |
12 | 15b96921a087 |
13 | 80ccb601566 |
14 | 3bc6b8bb9c3 |
15 | 1de6cb58e21 |
hex | 1033fafbce7 |
1113465011431 has 2 divisors, whose sum is σ = 1113465011432. Its totient is φ = 1113465011430.
The previous prime is 1113465011339. The next prime is 1113465011437. The reversal of 1113465011431 is 1341105643111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113465011431 - 211 = 1113465009383 is a prime.
It is a super-2 number, since 2×11134650114312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113465011393 and 1113465011402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113465011437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556732505715 + 556732505716.
It is an arithmetic number, because the mean of its divisors is an integer number (556732505716).
Almost surely, 21113465011431 is an apocalyptic number.
1113465011431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113465011431 is an equidigital number, since it uses as much as digits as its factorization.
1113465011431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 1113465011431 in words is "one trillion, one hundred thirteen billion, four hundred sixty-five million, eleven thousand, four hundred thirty-one".
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