Base | Representation |
---|---|
bin | 10000001100111111101… |
… | …011111011111010111111 |
3 | 10221110001021212020121022 |
4 | 100030333223323322333 |
5 | 121220334020340103 |
6 | 2211304015254355 |
7 | 143305462304006 |
oct | 20147753737277 |
9 | 3843037766538 |
10 | 1113465011903 |
11 | 39a243a75802 |
12 | 15b96921a3bb |
13 | 80ccb60183a |
14 | 3bc6b8bbc3d |
15 | 1de6cb59138 |
hex | 1033fafbebf |
1113465011903 has 2 divisors, whose sum is σ = 1113465011904. Its totient is φ = 1113465011902.
The previous prime is 1113465011843. The next prime is 1113465011929. The reversal of 1113465011903 is 3091105643111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113465011903 - 26 = 1113465011839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113465011993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556732505951 + 556732505952.
It is an arithmetic number, because the mean of its divisors is an integer number (556732505952).
Almost surely, 21113465011903 is an apocalyptic number.
1113465011903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113465011903 is an equidigital number, since it uses as much as digits as its factorization.
1113465011903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 35.
The spelling of 1113465011903 in words is "one trillion, one hundred thirteen billion, four hundred sixty-five million, eleven thousand, nine hundred three".
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