Base | Representation |
---|---|
bin | 110011110110100101… |
… | …0110000011011101101 |
3 | 101122102101200210002222 |
4 | 1213231022300123231 |
5 | 3311022404434123 |
6 | 123053245325125 |
7 | 11021302413665 |
oct | 1475512603355 |
9 | 348371623088 |
10 | 111353202413 |
11 | 43251a86112 |
12 | 196b7b667a5 |
13 | a667971aab |
14 | 5564bd31a5 |
15 | 2d6ace66c8 |
hex | 19ed2b06ed |
111353202413 has 2 divisors, whose sum is σ = 111353202414. Its totient is φ = 111353202412.
The previous prime is 111353202383. The next prime is 111353202419. The reversal of 111353202413 is 314202353111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107858382724 + 3494819689 = 328418^2 + 59117^2 .
It is an emirp because it is prime and its reverse (314202353111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111353202413 - 26 = 111353202349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111353202419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55676601206 + 55676601207.
It is an arithmetic number, because the mean of its divisors is an integer number (55676601207).
Almost surely, 2111353202413 is an apocalyptic number.
It is an amenable number.
111353202413 is a deficient number, since it is larger than the sum of its proper divisors (1).
111353202413 is an equidigital number, since it uses as much as digits as its factorization.
111353202413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 111353202413 its reverse (314202353111), we get a palindrome (425555555524).
The spelling of 111353202413 in words is "one hundred eleven billion, three hundred fifty-three million, two hundred two thousand, four hundred thirteen".
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