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11138608181713 is a prime number
BaseRepresentation
bin1010001000010110100011…
…0010001011000111010001
31110102211200202101212022011
42202011220302023013101
52424443332143303323
635405001141542521
72226511044244345
oct242055062130721
943384622355264
1011138608181713
113604947a32401
1212ba8a1414a41
1362a49b84061c
142a717bdc1625
15144b1a10020d
hexa2168c8b1d1

11138608181713 has 2 divisors, whose sum is σ = 11138608181714. Its totient is φ = 11138608181712.

The previous prime is 11138608181707. The next prime is 11138608181731. The reversal of 11138608181713 is 31718180683111.

It is a happy number.

Together with next prime (11138608181731) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9327600108544 + 1811008073169 = 3054112^2 + 1345737^2 .

It is a cyclic number.

It is not a de Polignac number, because 11138608181713 - 237 = 11001169228241 is a prime.

It is a super-2 number, since 2×111386081817132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11138608181783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5569304090856 + 5569304090857.

It is an arithmetic number, because the mean of its divisors is an integer number (5569304090857).

Almost surely, 211138608181713 is an apocalyptic number.

It is an amenable number.

11138608181713 is a deficient number, since it is larger than the sum of its proper divisors (1).

11138608181713 is an equidigital number, since it uses as much as digits as its factorization.

11138608181713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 193536, while the sum is 49.

The spelling of 11138608181713 in words is "eleven trillion, one hundred thirty-eight billion, six hundred eight million, one hundred eighty-one thousand, seven hundred thirteen".