Base | Representation |
---|---|
bin | 10100101111111111… |
… | …11000101001000111 |
3 | 1001202100221201202202 |
4 | 22113333320221013 |
5 | 140303322310122 |
6 | 5041225425115 |
7 | 543026534324 |
oct | 122777705107 |
9 | 31670851682 |
10 | 11140041287 |
11 | 47a72989a1 |
12 | 21aa93b19b |
13 | 1086c4a70b |
14 | 779725b4b |
15 | 453002e92 |
hex | 297ff8a47 |
11140041287 has 2 divisors, whose sum is σ = 11140041288. Its totient is φ = 11140041286.
The previous prime is 11140041109. The next prime is 11140041307. The reversal of 11140041287 is 78214004111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11140041287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11140041587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570020643 + 5570020644.
It is an arithmetic number, because the mean of its divisors is an integer number (5570020644).
Almost surely, 211140041287 is an apocalyptic number.
11140041287 is a deficient number, since it is larger than the sum of its proper divisors (1).
11140041287 is an equidigital number, since it uses as much as digits as its factorization.
11140041287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 29.
Adding to 11140041287 its reverse (78214004111), we get a palindrome (89354045398).
The spelling of 11140041287 in words is "eleven billion, one hundred forty million, forty-one thousand, two hundred eighty-seven".
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