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111401441233 is a prime number
BaseRepresentation
bin110011111000000001…
…0110001011111010001
3101122112202110120022221
41213300002301133101
53311122232104413
6123102131301041
711022426424645
oct1476002613721
9348482416287
10111401441233
1143277233705
121971014a781
13a674961684
14556b38cc25
152d7017468d
hex19f00b17d1

111401441233 has 2 divisors, whose sum is σ = 111401441234. Its totient is φ = 111401441232.

The previous prime is 111401441219. The next prime is 111401441279. The reversal of 111401441233 is 332144104111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66148239249 + 45253201984 = 257193^2 + 212728^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111401441233 is a prime.

It is a super-2 number, since 2×1114014412332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111401441198 and 111401441207.

It is not a weakly prime, because it can be changed into another prime (111401421233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55700720616 + 55700720617.

It is an arithmetic number, because the mean of its divisors is an integer number (55700720617).

Almost surely, 2111401441233 is an apocalyptic number.

It is an amenable number.

111401441233 is a deficient number, since it is larger than the sum of its proper divisors (1).

111401441233 is an equidigital number, since it uses as much as digits as its factorization.

111401441233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 111401441233 its reverse (332144104111), we get a palindrome (443545545344).

The spelling of 111401441233 in words is "one hundred eleven billion, four hundred one million, four hundred forty-one thousand, two hundred thirty-three".