1114021411 has 2 divisors, whose sum is σ = 1114021412. Its totient is φ = 1114021410.

The previous prime is 1114021393. The next prime is 1114021417. The reversal of 1114021411 is 1141204111.

It is a strong prime.

It is an emirp because it is prime and its reverse (1141204111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114021411 - 2⁵ = 1114021379 is a prime.

It is not a weakly prime, because it can be changed into another prime (1114021417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557010705 + 557010706.

It is an arithmetic number, because the mean of its divisors is an integer number (557010706).

Almost surely, 2^1114021411 is an apocalyptic number.

1114021411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114021411 is an equidigital number, since it uses as much as digits as its factorization.

1114021411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 16.

The square root of 1114021411 is about 33376.9592833140. The cubic root of 1114021411 is about 1036.6476781065.

Adding to 1114021411 its reverse (1141204111), we get a palindrome (2255225522).

The spelling of 1114021411 in words is "one billion, one hundred fourteen million, twenty-one thousand, four hundred eleven".