111403214143 has 4 divisors (see below), whose sum is σ = 119972692168. Its totient is φ = 102833736120.

The previous prime is 111403214137. The next prime is 111403214149. The reversal of 111403214143 is 341412304111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341412304111 = 53 ⋅6441741587.

It is an interprime number because it is at equal distance from previous prime (111403214137) and next prime (111403214149).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111403214143 is a prime.

It is a super-2 number, since 2×111403214143² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111403214149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4284738993 + ... + 4284739018.

It is an arithmetic number, because the mean of its divisors is an integer number (29993173042).

Almost surely, 2^111403214143 is an apocalyptic number.

111403214143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

111403214143 is a deficient number, since it is larger than the sum of its proper divisors (8569478025).

111403214143 is an equidigital number, since it uses as much as digits as its factorization.

111403214143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8569478024.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 111403214143 its reverse (341412304111), we get a palindrome (452815518254).

The spelling of 111403214143 in words is "one hundred eleven billion, four hundred three million, two hundred fourteen thousand, one hundred forty-three".