11140332433 has 2 divisors, whose sum is σ = 11140332434. Its totient is φ = 11140332432.

The previous prime is 11140332353. The next prime is 11140332451. The reversal of 11140332433 is 33423304111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11138058369 + 2274064 = 105537^2 + 1508^2 .

It is a cyclic number.

It is not a de Polignac number, because 11140332433 - 2¹⁷ = 11140201361 is a prime.

It is a super-4 number, since 4×11140332433⁴ (a number of 41 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11140332398 and 11140332407.

It is not a weakly prime, because it can be changed into another prime (11140330433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570166216 + 5570166217.

It is an arithmetic number, because the mean of its divisors is an integer number (5570166217).

Almost surely, 2^11140332433 is an apocalyptic number.

It is an amenable number.

11140332433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140332433 is an equidigital number, since it uses as much as digits as its factorization.

11140332433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11140332433 its reverse (33423304111), we get a palindrome (44563636544).

The spelling of 11140332433 in words is "eleven billion, one hundred forty million, three hundred thirty-two thousand, four hundred thirty-three".